If you need a 1% active ingredient mixture, how many gallons of 25% emulsifiable concentrate (with 2 pounds pesticide per gallon) would you require for a 50-gallon tank?

To determine how many gallons of a 25% emulsifiable concentrate are needed to achieve a 1% active ingredient mixture in a 50-gallon tank, you begin by calculating the total amount of active ingredient required.

First, a 1% solution in a 50-gallon tank means you need 1% of 50 gallons, which is 0.5 gallons of active ingredient. Since the emulsifiable concentrate contains 25% active ingredient, you can find out how much concentrate is needed to reach this amount.

The equation to find the required volume of concentrate is:

Volume of concentrate = Amount of active ingredient required / Concentration of emulsifiable concentrate

Plugging in the numbers:

1. You need 0.5 gallons of active ingredient.

2. The emulsifiable concentrate has 25% active ingredient, or 0.25 when expressed as a decimal.

Now, substituting these values into the equation:

Volume of concentrate = 0.5 gallons / 0.25 = 2 gallons

Thus, you would require 2 gallons of the 25% emulsifiable concentrate to achieve the desired 1% active ingredient mixture in a 50-gallon tank.

In the context of the choices provided,